1.

For x > 0, Let A=⎡⎢⎣x+1x000x00016⎤⎥⎦B=⎡⎢⎢⎢⎣5xx2+10003x00014⎤⎥⎥⎥⎦X=(AB)−1+(AB)−2+(AB)−3+...∞Z=X−1−2I (I is identity matrix of order 3)(P) minimum value of [Tr(Ax)]is(1)24(when [.])→represent integer function(Q) det(X−1) is(2)12(R) If Tr(z+z2+−−−+z10)=2a+b,(a,b∈N)then a + b is (3)6(S) If value of |adj(√5X−1)|=kthen number of positive divisors(4)19of k which are odd is

Answer»

For x > 0, Let A=⎡⎢⎣x+1x000x00016⎤⎥⎦B=⎡⎢
⎢
⎢
⎣
5xx2+10003x00014⎤⎥
⎥
⎥
⎦


X=(AB)−1+(AB)−2+(AB)−3+...∞

Z=X−1−2I (I is identity matrix of order 3)

(P) minimum value of [Tr(Ax)]is(1)24(when [.])→represent integer function(Q) det(X−1) is(2)12(R) If Tr(z+z2+−−−+z10)=2a+b,(a,b∈N)then a + b is (3)6(S) If value of |adj(√5X−1)|=kthen number of positive divisors(4)19of k which are odd is



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