1.

For what values of k are the roots of kx^2+(k-1)x+(k-1) =0 equals

Answer»

For equal roots,

Discriminent = 0

=> b^2 - 4ac = 0

=> (K-1)^2 - 4(k-1)(k) = 0

=> (k-1)^2 = 4(k-1)(k)

=> k - 1 = 4k

=> - 3k = 1

=> k = - 1/3


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