For what values of b is the polynomial x cube - 3 x + b x - 6 divisibl

1.	For what values of b is the polynomial x cube - 3 x + b x - 6 divisible by x - 3
Answer» <P>p(X) = -3x+bx-6 g(X)= x-3 x-3=0 x=3 Substituting value of x in p(X) -3(3)+B(3)-6=0 -27+3b-6=0 -33+3b=0 3b=33 b=11 PLS MARK ME THE BRAINLIEST IF U LIKE THE ANSWER

For what values of b is the polynomial x cube - 3 x + b x - 6 divisible by x - 3

Answer»

<P>p(X) = -3x+bx-6

g(X)= x-3

x-3=0

x=3

Substituting value of x in p(X)

-3(3)+B(3)-6=0

-27+3b-6=0

-33+3b=0

3b=33

b=11

PLS MARK ME THE BRAINLIEST IF U LIKE THE ANSWER

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For what values of b is the polynomial x cube - 3 x + b x - 6 divisible by x - 3​

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For what values of b is the polynomial x cube - 3 x + b x - 6 divisible by x - 3