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For what value of p the point (p,0) lies on the line 3x + y = 11 ?

Answer»

<P>Question :–

▪︎ For what VALUE of p the point (p,0) lies on the line 3x + y = 11 ?

Answer :–

\\  \longrightarrow \large {  \red{ \boxed{\bold{ \: p= \frac{11}{3} }}}}  \\

EXPLANATION :–

GIVEN :–

▪︎ A point (p,0) lies on the line 3x + y = 11 .

TO FIND :–

▪︎ Value of p = ?

SOLUTION :–

▪︎ If a point lies on the line , then the will satisfy the equation.

• Hence , (p,0) will satisfy the equation 3x + y = 11.

\\  { \bold{ \implies \: 3(p) + 0 = 11}}  \\

\\  { \bold{ \implies \: 3p= 11}}  \\

\\  \implies \large {  \boxed{\bold{ \: p= \frac{11}{3} }}}  \\

Hence , Value of { \bold{  \: p \: \: is \: \:  \frac{11}{3} \: . }}  \\

VERIFICATION :–

• We have to satisfy that a Point { \bold { (\dfrac{11}{3} , 0)}} will satisfy the given equation .

\\  { \bold{ \implies \:  \cancel3( \frac{11}{ \cancel3} ) + 0 = 11}}  \\

\\  { \bold{ \implies \:  11 = 11 \:   \:  \:  \:  \:  \:  \: \: (Verified)}}  \\



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