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For what value of μ do the simultaneous equations 5x + 7y = 2, 15x + 21y = μ have no solution?1. μ = 02. μ ≠ 63. μ ≠ 04. μ = 6 |
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Answer» Correct Answer - Option 2 : μ ≠ 6 Concept: System of equations a1x + b1y = c1 a2x + b2y = c2 For unique solution \(\frac {a_1}{a_2}≠ \frac {b_1}{b_2}\) For Infinite solution \(\frac {a_1}{a_2}= \frac {b_1}{b_2}= \frac {c_1}{c_2}\) For no solution \(\frac {a_1}{a_2}=\frac {b_1}{b_2}≠ \frac {c_1}{c_2}\) Calculation: Given: 5x + 7y = 2, 15x + 21y = μ Here For no solution \(\frac 5{15}=\frac 7{21}≠ \frac 2{μ}\) Hence for no solution μ ≠ 6 |
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