1.

For what value of μ do the simultaneous equations 5x + 7y = 2, 15x + 21y = μ have no solution?1. μ = 02. μ ≠ 63. μ ≠ 04. μ = 6

Answer» Correct Answer - Option 2 : μ ≠ 6

Concept:

System of equations

a1x + b1y = c1

a2x + b2y = c2

For unique solution

\(\frac {a_1}{a_2}≠ \frac {b_1}{b_2}\)

For Infinite solution

\(\frac {a_1}{a_2}= \frac {b_1}{b_2}= \frac {c_1}{c_2}\)

For no solution

\(\frac {a_1}{a_2}=\frac {b_1}{b_2}≠ \frac {c_1}{c_2}\)

Calculation:

Given:

5x + 7y = 2, 15x + 21y = μ

Here For no solution

\(\frac 5{15}=\frac 7{21}≠ \frac 2{μ}\)

Hence for no solution μ ≠ 6



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