1.

For what value of k, the pair of linear equations 3x + y = 3 and 6x + ky = 8 does not have a solution.

Answer»

\(\frac{3}{6}=\frac{1}{k}\) ≠ \(\frac{3}{8}\)

\(\frac{3}{6}=\frac{1}{k}\)

k = 2



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