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For what value of k, the pair of linear equations 3x + y = 3 and 6x + ky = 8 does not have a solution. |
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Answer» \(\frac{3}{6}=\frac{1}{k}\) ≠ \(\frac{3}{8}\) \(\frac{3}{6}=\frac{1}{k}\) k = 2 |
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