1.

For what value of k the following pair has infinitenumber of solutions. (k-3)x + 3y = k and k(x+y)=12​

Answer»

Answer:

k=+-6

Step-by-step explanation:

on expanding, (k-3)x +3Y =k  ...eq 1

                         kx+ky =12  ...eq 2

Here LET consider that,

     a=(k-3)  ,  b= 3  ,  c=k

     A=k   , B=k   , C=12

 These EQUATION has infinite solution,so,

a/A=b/B=c/C

(k-3)/k = 3/k = k/12

Now,On equating,

3/k = k/12

k2 = 36

On taking square root both side,

       k= +-6

"k2 means k has power of 2 on it"

thanq...


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