1.

For what value of k for which the given system of equations has infinitely many solution (1) 5x+2y = K , 10x+4y =3Please help me​

Answer»

Answer:

3/2 is the REQUIRED value of k .

Step-by-step explanation:

According to the QUESTION

1st equation = 5x+2y=k

➻ 5x+2y-k = 0

where,

a₁ = 5 , b₁ = 2 and c₁ = -k

2nd equation = 10x+4y = 3

➻ 10x+4y-3 = 0

where,

a₂= 10 , b₂ = 4 and c₂ = -3

As we know the condition for Equation which INFINITELY MANY solution .

  • a₁/a₂ = b₁/b₂ = c₁/c₂

Substitute the value we get

➻ 5/10 = 2/4 = -k/-3

➻ 1/2 = k/3

➻ k = 3/2

  • Hence, the given system of equations will have infinitely many solutions if k = 3/2.


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