For what value of K does the system of equation has . x+2y=3 , 5x+ky+7

1.	For what value of K does the system of equation has . x+2y=3 , 5x+ky+7=0. 1) a unique solution 2)no solution
Answer» Answer: for UNIQUE solution a1/a2not=to b1/b2 1/5 not=to2/K k not=to 10 all VALUE for k except 10 2) for no solution a1/a2=b1/b2 not=to c1/c2 1/5=2/k k=10

For what value of K does the system of equation has . x+2y=3 , 5x+ky+7=0. 1) a unique solution 2)no solution

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Answer:

for UNIQUE solution a1/a2not=to b1/b2

1/5 not=to2/K

k not=to 10

all VALUE for k except 10

2) for no solution

a1/a2=b1/b2 not=to c1/c2

1/5=2/k

k=10

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For what value of K does the system of equation has . x+2y=3 , 5x+ky+7=0. 1) a unique solution 2)no solution​

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For what value of K does the system of equation has . x+2y=3 , 5x+ky+7=0. 1) a unique solution 2)no solution