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For what value of 'k' does the pair of linear equations 2x - y - 3 = 0 and 2kx + 7y - 5 = 0 have a unique solution x = 1 & y = - 1? A) 3 B) 4 C) 6 D) - 6 |
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Answer» Answer: 6 Step-by-step explanation: Given: 2x-y-3=0 2kx+7y-5=0 x=1 y=-1 substitute..... 2x1-(-1)-3=0 2kx1+7x(-1)-5=0 => 2+1-3=0 ; 2k-7-5=0 => 3-3=0 ; 2k-12=0 => 0 ; 2k=12 => k=12/2 => k=6 Hope this HELPS you to UNDERSTAND easier..... |
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