1.

For what the value of k will the consecutive term 2k+1,3 k+3,5k+1 form an A.P​

Answer»

Answer:

Step-by-step explanation:

6 is the value of k for the consecutive terms 2k+1, 3k+3, 5k-1 which forms an AP.

Given:

Consecutive terms = 2k + 1, 3k + 3, 5k-1

To FIND:

The value of k which forms AP in the given consecutive terms  

Solution:

Consecutive terms = 2k + 1, 3k + 3, 5k-1

THEREFORE, by following the rule of AP that the difference of any two consecutive terms of an AP is same, we can write:

The formula for the finding the common difference is  

3k + 3 - 2k - 1 = 5k - 1 - 3k - 3

k + 2 = 2k - 4

By SEPARATING the common terms

We get,

2k - k = 4 + 2  

     k = 6.  

Therefore, 6 is the value of k for the given consecutive terms.


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