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For what distance is ray optics a good approximation when the aperture is 3mm wide and wavelength is 500 nm? |
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Answer» Here, a = 3mm = 3 × 10−3m λ = 500 nm = 5× 10−7m Fresnel distance, ZF = ? ZF = \(\frac{a^2}{\lambda}\) = \(\frac{(3\times 10^{-3})^2}{5\times 10^{-7}}\) = 18m |
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