For water at 25oC,dps/dTs=0.189kPa/K (ps is the saturation pressure in kPa an Ts is the saturation temperature in K) and the specific volume of dry saturated vapour is 43.38m3/kg. Assume that the specific volume of liquid is negligible in comparison with that of vapour. Using the Clausius-Clapeyron equation, an estimate of the enthalpy of evaporation of water at 25oC (in kJ/kg) is 2443.2478

For water at 25oC,dps/dTs=0.189kPa/K (ps is the saturation pressure in

1.	For water at 25oC,dps/dTs=0.189kPa/K (ps is the saturation pressure in kPa an Ts is the saturation temperature in K) and the specific volume of dry saturated vapour is 43.38m3/kg. Assume that the specific volume of liquid is negligible in comparison with that of vapour. Using the Clausius-Clapeyron equation, an estimate of the enthalpy of evaporation of water at 25oC (in kJ/kg) is 2443.2478
Answer» For water at $25^{o} C, d p_{s} / d T_{s} = 0.189 k P a / K$ ( $p_{s}$ is the saturation pressure in $k P a$ an $T_{s}$ is the saturation temperature in $K$ ) and the specific volume of dry saturated vapour is $43.38 m^{3} / k g$ . Assume that the specific volume of liquid is negligible in comparison with that of vapour. Using the Clausius-Clapeyron equation, an estimate of the enthalpy of evaporation of water at $25^{o} C$ (in $k J / k g$ ) is 2443.2478