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For three events A, B and C, P(Exactly one of A or B occurs) = P(Exactly one of B or C occurs) = P(Exactly one of C or A occurs) = 1/4 and P (All the three events occur simultaneously) = 1/6.Then the probability that at least one of the events occurs, is :(1) 7/32(2) 7/16(3) 7/64(4) 3/16 |
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Answer» Solution: P(A) + P(B) – 2P (A ∩ B) = 1/4 |
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