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for the system A(g) +2b(g) = c(g) the equilibrium concentration are. (A) 0.06mole/litre (B) 0.12mole/litre (C) 0.216 mole/litre. The k (eq) for the reaction is |
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Answer» K(EQ) =(C)/((a)*(b^2)) =0.216/0.06*0.12^2 =0.216/0.06*0.0144 =0.216/0.000864 =216*10^-3/864*10^-6 =250 it is OPTION (a) |
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