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For the series, `S=1+1/((1+3))(1+2)^2+1/((1+3+5))(1+2+3)^2+1/((1+3+5+7))(1+2+3+4)^2`+...7th term is 167th term is 18Sum of first 10 terms is `(505)/4`Sum of first 10 terms is `(45)/4`A. `7^(th)` term is 16B. `7^(th)` term is 18C. sum of first 10 term is `505/4`D. sum of first `10` term is `405/4` |
| Answer» Correct Answer - A | |