1.

For the reversible reaction, A+2B→3C, if equilibrium constant is 1×102 at 27°C then the value of ΔrG∘ at the same temperature will be:(R=2 cal K−1 mol−1)

Answer»

For the reversible reaction, A+2B3C, if equilibrium constant is 1×102 at 27°C then the value of ΔrG at the same temperature will be:

(R=2 cal K1 mol1)



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