1.

For the reaction PCI_3 (g) +CI_2(g) hArr PCI_5(g), the value of K_p at 250^@C is 0.61 atm^(-1). The value of K_c at this temperature will be

Answer»

`15 (mol//I)^(-1)`
`26 (mol//I)^(-1)`
`35 (mol//I)^(-1)`
`52 (mol//I)^(-1)`

Solution :`PCI_3(g)+CI_2(g) hArrPCI_5(g)`
`DELTAN=-,K_p=0.61 ATM ^(-1)`
`K_c=K_p(RT)^(-Deltan)`
`=0.61(0.0821 xx 523)^(+1)=26 mol//I`.


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