For the reaction H2(g) + 12O2(g) → H2O(l),ΔH = −285.8kJmol−1 Δ – InterviewSolution

1.	For the reaction H2(g) + 12O2(g) → H2O(l),ΔH = −285.8kJmol−1 ΔS = −0.163kJmol−1K−1. What is the value of free energy change 27∘C for the reaction.
Answer» For the reaction $H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l), Δ H = - 285.8 k J m o l^{- 1} Δ S = - 0.163 k J m o l^{- 1} K^{- 1}$ . What is the value of free energy change $27^{\circ} C$ for the reaction.

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