1.

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) at 712K the value of equlibrium constant (K_(c)) is 50. When the equlibrium concentration of both is 0.5M, the value of K_(p) under the same conditions will be

Answer»

<P>`0.002`
`0.2`
`50.0`
`50//RT`

Solution :For the reaction `H_(2)+I_(2)hArr2HI Deltan=0`
So `K_(p)=K_(C)THEREFORE 50.0`


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