1.

For the reaction, following data is given: AtoB,K_(1)=10^(15)"exp"^(((-2000)/T)),CtoD,K_(2)=10^(14)"exp"^(((-1000)/T)) The temperature at which K_(1)=K_(2) is

Answer»

`1000K`
`2000K`
`2000/2.303K`
1000/2.303K

Solution :`K_(A)=K_(C),10^(15),E^(((-2000)/T))=10^(14).e^(((-1000)/T))`
`10=(e^(-1000+2000)/T),2.303xxlog_(10)^(10)=1000/T,T=(1000/2.303)`Kelving


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