For the reaction C2H4 + 3O2 gives 2CO2 + H2O(l) ∆H=-1415kJ then ∆H

1.	For the reaction C2H4 + 3O2 gives 2CO2 + H2O(l) ∆H=-1415kJ then ∆H at 27°C
Answer» : The enthalpy change is -1415 kJExplanation :The GIVEN balanced CHEMICAL reaction is,FORMULA used :where, = change in enthalpy = ? = change in internal energy = = change in MOLES = [(2+2)-(3+1)] = 0 (from reaction)R = gas constant = 8.314 J/mol.KT = temperature = Now put all the given values in the above formula, we GET:Therefore, the enthalpy change is -1415 kJmark me brainlest ☺️ plzzzzzzz

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