1.

For the reaction: C_(12) H_(22)O_(11) +H_(2)O overset(H^(+))to C_(6)H_(12)O_(6)+C_(6)H_(12)O_(6) write: (i) rate of reaction expression. (ii) rate law equation. (iii) molecularity. (iv) order of reaction.

Answer»

Solution :(i) RATE `=(-d[C_(12)H_(22)O_(11)])/(dt)= -(d[H_(2)O])/(dt)= (d[C_(6)H_(12)O_(6)])/(dt)= (d[C_(6)H_(12)O_(6)])/(dt)`
(ii) Rate `=k[C_(12)H_(22)O_(11)]`
(iii) Two
(iv) The reaction is of first ORDER because `H_(2)O` is taken in such large EXCESS that its concentration does not change with time.


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