For the reaction,aP→bQGiven that: log[(ROD)P]=log[(ROA)Q]+1where (RO – InterviewSolution

1.	For the reaction,aP→bQGiven that: log[(ROD)P]=log[(ROA)Q]+1where (ROD)P is rate of disappearance of 'P',−d[P]dt and (ROA)Q is rate of appearance of 'Q',+d[Q]dt. Then a:b will be:
Answer» For the reaction, $a P \to b Q$ Given that: $l o g [(R O D)_{P}] = l o g [(R O A)_{Q}] + 1$ where $(R O D)_{P}$ is rate of disappearance of 'P', $\frac{- d [P]}{d t}$ and $(R O A)_{Q}$ is rate of appearance of 'Q', $\frac{+ d [Q]}{d t}$ . Then $a : b$ will be:

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