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For the reaction A 3B are equal, then percent of B reacted is (1) 10% (3) 40% 2C + D, initial mole of A is twice that of B. If at equilibrium moles of B and (2) 20% (4) 60% |
| Answer» For the reaction A 3B are equal, then percent of B reacted is (1) 10% (3) 40% 2C + D, initial mole of A is twice that of B. If at equilibrium moles of B and (2) 20% (4) 60% | |