For the reaction:4NH3(g)+3O2(g)→2N2(g)+6H2O(l) at 298 K. Given that – InterviewSolution

1.	For the reaction:4NH3(g)+3O2(g)→2N2(g)+6H2O(l) at 298 K. Given that heat of formation of NH3(g) and H2O(l) are −46 kJ mol−1 and −286 kJ mol−1 respectively. Calculate heat of reaction at 298 K.
Answer» For the reaction: $4 N H_{3} (g) + 3 O_{2} (g) \to 2 N_{2} (g) + 6 H_{2} O (l)$ at $298 K$ . Given that heat of formation of $N H_{3} (g$ ) and $H_{2} O (l)$ are $- 46 k J m o l^{- 1}$ and $- 286 k J m o l^{- 1}$ respectively. Calculate heat of reaction at $298 K$ .

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