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For the reaction, 2Fe(NO3)3+3Na2CO3→Fe2(CO3)3+6NaNO3, initially if 3 moles of Fe(NO3)3 and 3.6 moles of Na2CO3 is taken and 6.3 moles of NaNO3 is obtained, then the % yield of given reaction is: |
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Answer» For the reaction, 2Fe(NO3)3+3Na2CO3→Fe2(CO3)3+6NaNO3, initially if 3 moles of Fe(NO3)3 and 3.6 moles of Na2CO3 is taken and 6.3 moles of NaNO3 is obtained, then the % yield of given reaction is: |
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