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For the network shown in figure Determine the value of R and the current through it, if the current through the branch AO is zero.

Answer» Since no current flows through arm Ao, so the bridge fomerd by resistance `2 Oemga, 2.5 Omega, 4 Omega` and R will form a balanced Wheatstone bridge.
So, `2/2.5 = 4/R or R =( 4xx2.5)/2= 5 Omega`
The equivalent resistance `R_(eq)` of the network between B and C is
`R_(eq) = ((2+2.5 ) xx (4+5))/((2 +2.5) + (4+5)) + 2 = 3 +2 = 5 Omega`
Current in the circuit, `I=10/5 = 2A`


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