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For the formation of 3.65g of HCI gas , what volume of hydrogen gas and chlorine gas , are required at NTP conditions?A. 1L, 1LB. 1.12 L, 2.24 LC. 3.65 L,1.83 LD. 1.12L,1.12 L |
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Answer» Correct Answer - D `H_(2)+CI_(2) to 2HCI" "n _(HCI) (3.65)/(36.5) = 0.1 ` `{:(2gm,71 gm,73gm,),(1"mole",1"mole",2 "mole",):}` here 2 mole HCI produced by 1 mole `H _(2)` 1 mole HCI produce by 0.05 mole `n_(H2) = V _(CI2) = 0.05 xx 22.4 =1.12L` |
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