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For the following repeater machines, how many times the base machine is applied and how much the total stretch is? |
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Answer» In machine (a), (x 100 2) = 10000 stretch. Since, it is two times the base machine. In machine (b), (x 7 5) = 16807 stretch. Since, it is fair times the base machine. In machine (c), (x 57) = 78125 stretch. Since, it is 7 times the base machine. |
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