For the following reaction,Pb(s)+Hg2SO4(s)⇌PbSO4(s)+2Hg(l);Eocell=0. – InterviewSolution

1.	For the following reaction,Pb(s)+Hg2SO4(s)⇌PbSO4(s)+2Hg(l);Eocell=0.92 VKsp(PbSO4)=2×10−8, Ksp(Hg2SO4)=1×10−6Hence, Ecell is:(take √2=1.4, log0.14=−0.85)
Answer» For the following reaction, $P b (s) + H g_{2} S O_{4} (s) ⇌ P b S O_{4} (s) + 2 H g (l);$ $E_{c e l l}^{o} = 0.92 V$ $K_{s p} (P b S O_{4}) = 2 \times 10^{- 8}, K_{s p} (H g_{2} S O_{4}) = 1 \times 10^{- 6}$ Hence, $E_{c e l l}$ is: (take $\sqrt{2} = 1.4, l o g 0.14 = - 0.85$ )

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