For the equilibrium N2O4⇌2NO2 (GoN2O4)298K=100kJmol−1 and (GoNO2)2 – InterviewSolution

1.	For the equilibrium N2O4⇌2NO2 (GoN2O4)298K=100kJmol−1 and (GoNO2)298K=50kJmol−1. When 5 mole/litre of each is taken, calculate the value of △G in kJ mol−1 for the reaction at 298 K.(nearest integer)
Answer» For the equilibrium $N_{2} O_{4} ⇌ 2 N O_{2}$ $(G_{N_{2} O_{4}}^{o})_{298 K} = 100 k J m o l^{- 1} a n d (G_{N O_{2}}^{o})_{298 K} = 50 k J m o l^{- 1} .$ When 5 mole/litre of each is taken, calculate the value of $△ G$ in $k J m o l^{- 1}$ for the reaction at 298 K.(nearest integer)

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