For the combustion of 1 mole of liquid benzene at 25∘C, the heat of – InterviewSolution

1.	For the combustion of 1 mole of liquid benzene at 25∘C, the heat of the reaction at constant pressure is given by, C6H6(l)+712O2(g)⟶6CO2(g)+3H2O(l) ΔH=−780980 cal What would be the heat of the reaction at constant volume?
Answer» For the combustion of 1 mole of liquid benzene at $25^{\circ} C$ , the heat of the reaction at constant pressure is given by, $C_{6} H_{6} (l) + 7 \frac{1}{2} O_{2} (g) ⟶ 6 C O_{2} (g) + 3 H_{2} O (l)$ $Δ H = - 780980 c a l$ What would be the heat of the reaction at constant volume?

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