1.

For the combustion of 1 mole of liquid benzene at 25oC, the heat of reaction at constant pressure is given by C6H6(l)+712O2(g)→6CO2(g)+3H2O(l); △U=−780980 calWhat would be the heat of reaction at constant volume?

Answer»

For the combustion of 1 mole of liquid benzene at 25oC, the heat of reaction at constant pressure is given by

C6H6(l)+712O2(g)6CO2(g)+3H2O(l); U=780980 cal

What would be the heat of reaction at constant volume?



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