For the cell reaction: Fe(s)|Fe2+(0.1 M)||H+(1 M)|H2(1 atm)|Pt(s)E0(Fe – InterviewSolution

1.	For the cell reaction: Fe(s)\|Fe2+(0.1 M)\|\|H+(1 M)\|H2(1 atm)\|Pt(s)E0(Fe/Fe2+)=0.44 V, the cell emf at 298 K is:
Answer» For the cell reaction: $F e (s) \| F e^{2 +} (0.1 M) \| \| H^{+} (1 M) \| H_{2} (1 atm) \| P t (s)$ $E_{(F e / F e^{2 +})}^{0} = 0.44 V,$ the cell emf at $298 K$ is:

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