1.

For real constants a,b,c,d, suppose f(x) is a function of the form f(x)=ax8+bx6+cx4+dx2+15x+1x for x≠0. If f(5)=2, then the value of f(–5) is

Answer» For real constants a,b,c,d, suppose f(x) is a function of the form f(x)=ax8+bx6+cx4+dx2+15x+1x for x0. If f(5)=2, then the value of f(5) is


Discussion

No Comment Found