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For n>0, the value of nC0−22⋅ nC1+32⋅ nC2−42 nC3⋯ upto (n+1) terms is kn(n+1)⋅2n, then k=

Answer» For n>0, the value of nC022 nC1+32 nC242 nC3 upto (n+1) terms is kn(n+1)2n, then k=


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