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For n>0, the value of nC0−22⋅ nC1+32⋅ nC2−42 nC3⋯ upto (n+1) terms is kn(n+1)⋅2n, then k= |
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Answer» For n>0, the value of nC0−22⋅ nC1+32⋅ nC2−42 nC3⋯ upto (n+1) terms is kn(n+1)⋅2n, then k= |
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