For f(x)=ax^2+bx+c,if f(1)=8 and f(-1)=4find a+c

1.	For f(x)=ax^2+bx+c,if f(1)=8 and f(-1)=4find a+c
Answer» ANSWER: put x=1 in f (x) we get a+ b+ c=8.........eq1 as f(1)=8 similarly put x= -1 in f( x) we get a-b+c=4 ........eq2 as f (-1) =4 now adding eq1 and eq2 we get a+b+c+a-b+c=8+4 =12 2a+2c=12 a+c=6 i *hope* my *answer* *may* *HELP* *you. please* *FOLLOW* me to *GIVE* me a *support* to *help* *more* *PEOPLE*.

Answer»

ANSWER:

put x=1 in f (x)

we get

a+ b+ c=8.........eq1

as f(1)=8

similarly

put x= -1 in f( x)

we get

a-b+c=4 ........eq2

as f (-1) =4

now adding eq1 and eq2

we get

a+b+c+a-b+c=8+4 =12

2a+2c=12

a+c=6

i hope my answer may HELP you.

please FOLLOW me to GIVE me a support to help more PEOPLE.

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For f(x)=ax^2+bx+c,if f(1)=8 and f(-1)=4find a+c

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