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For certain values of a,m and b, the functionf(x)=⎧⎨⎩3,x=0−x2+3x+a,0<x<1mx+b,1≤x≤2 satisfies the hypothesis of the mean value theorem for the interval [0,2]. Then the value of a+b+m is |
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Answer» For certain values of a,m and b, the function |
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