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For any two sets A and B, prove the following: A ∩ (A ∪ B’) = ϕ |
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Answer» = A∩ (A ∪ B’) = A∩( A’∩ B’) [By De–morgan’s law] = (A ∩ A’) ∩ B’ [∴ A ∩ A’ = ϕ ] = ϕ ∩ B’ = ϕ = RHS |
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