For any positive integer n prove that n^3-n is divisible by 6

1.	For any positive integer n prove that n^3-n is divisible by 6
Answer» ${<klux>N</klux>}^{3} - n \\ n(n + 1)(n - 1)$ These are 3 CONSECUTIVE numbers and n consecutive numbers are DIVISIBLE by n factorial. Now 3 consecutive numbers are divisible by 3!=6.

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For any positive integer n prove that n^3-n is divisible by 6

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