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For any positive integer a, b such that a > b, the difference of the squares of 2a + 1 and 2b+ 1 is always divisible by k, where k is an integer and 4 < k< 10. Find the value of 24 ×\sqrt[3]{k^2}. |
| Answer» For any positive integer a, b such that a > b, the difference of the squares of 2a + 1 and 2b+ 1 is always divisible by k, where k is an integer and 4 < k< 10. Find the value of 24 ×\sqrt[3]{k^2}. | |