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| 1. |
For an AP Tm-Tn =............. |
| Answer» Let \'a\' be the first term and \'d\' be common difference of the A.P⇒Tm\u200b=a+(m−1)d=n⇒a−d=n−md...(1)and\xa0Tn\u200b=a+(n−1)d=m⇒a−d=m−nd..(2)Using (1) and (2) we get,\xa0d=−1\xa0and\xa0a=n+m−1∴Tp\u200b=a+(p−1)=n+m−1+(p−1)(−1)=n+m−pHence, option \'A\' is correct. | |