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For an AP, a = −10, d = 4. find S10 terma. 90 b. 80 c. 100 d. 110​

Answer»

given÷

a=-10,d=4

to find S10

S10=n/2(2A+(n-1)d)

S10=10/2(2×-10+9×4)

S10=5(-20+36)

S10=5(16)

S10=80

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