1.

For an adiabatic change the value of (dP)/(P) is equal to (dV=" change in vol.," gamma =(C_(p))/(C_(v))):

Answer»

`GAMMA^(1//2) cdot (dV)/(V)`
`-(dV)/(V)`
`-gamma cdot (dV)/(V)`
`-gamma^(2)(dV)/(V)`

SOLUTION :Here `(d)/(DP) (P. V^(gamma)) =(d)/(dP)` (constant)
or `V^(gamma) +gamma V^(gamma-1)P(dV)/(dP)=0`
or `V^(gamma) =-gamma V^(gamma-1)P. (dV)/(dP)`
or `(dP)/(P) =(-gamma V^(gamma-1))/(V^(gamma)). dV =-gamma. (dV)/(V).`
`therefore` Correct choice is (C ).


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