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For all n ∈ N, 3 × 52n + 1 + 23n + 1 is divisible by A. 19 B. 17 C. 23 D. 25 |
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Answer» Given for all n€ N 3 × 52n+1 + 23n+1 For n=1, 3 × 53 + 24 3 × 125 + 16 375 + 16 = 391 For n=2, 3 × 55 + 27 3 × 3125 +128 9375 + 128 = 9503 H.C.F of 391, 9503 = 17 |
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