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For a transistor in saturation, which is true?(a) IC = βIB(b) IC > βIB(c) IC < βIB(d) IC = (β+1)IBThis question was posed to me during a job interview.My question is taken from Transistor Switching Network topic in portion Transistor Biasing and Low Frequencies of Analog Circuits

Answer»

The correct CHOICE is (c) IC < βIB

Easiest explanation: At saturation, collector current REMAINS constant. However, the base current increases with the INPUT voltage being applied and HENCE BJT cannot satisfy the relation IC = βIB. In the saturation region, βIB > IC is the correct relation.



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