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For a transistor beta=45, the change in the voltage across 5kOmega resistor which is connected in collector circuit is 5 V. Find the change in base current. |
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Answer» Solution :`BETA=((DeltaI_(C))/(DeltaI_(B)))_(V_(CE))` (If only d.c. values are considered) `THEREFORE I_(C)=betaI_(B)=40xx25xx10^(-6)=1000xx10^(-6)A` `therefore I_(E)=I_(B)+I_(C)=(25xx10^(-6)+1000xx10^(-6))" AMP"` `=1025muA=1.025mA` |
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