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For a transistor beta=40 and I_(B)=25muA .Find the value of I_(E) |
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Answer» Solution :`beta=((deltaI_(C))/(deltaI_(B)))_(C_(CE))`(if only d.c values are considered) `therefore I_(C)=betaI_(B)=40xx25xx10^(-6)=1000xx10^(-6)A` `therefore I_(E)=I_(B)+I_(C)=(25xx10^(-6)+1000xx10^(-6))amp` |
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