For a tightly coupled oscillator, the spring constant is equal to ?

1.	For a tightly coupled oscillator, the spring constant is equal to ?
Answer» F = -KX. The proportional CONSTANT k is CALLED the spring constant. It is a measure of the spring's stiffness. When a spring is stretched or compressed, so that its length CHANGES by an amount x from its equilibrium length, then it exerts a force F = -kx in a direction TOWARDS its equilibrium position.

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For a tightly coupled oscillator, the spring constant is equal to ?

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